如何根据离散的数据点获取线性的线段？-灵析社区

用js实现了下，思路应该是相通的 // 在一条直线上的点都满足 y = ax + b var array = [0, 1, 2, 3, 4, 5, 6, 0, 10, 11, 12, 13, 14, 15] var slopes = [] async function main() { for (let i = 0; i item.a == a && item.b == b) if (cur) { cur.flag++ } else { slopes.push({ a, b, flag: 1, points: [] }) } } } } slopes = slopes.sort((cur, pre) => pre.flag - cur.flag) slopes = slopes.filter(item => item.flag > 5) for (const line of slopes) { var a = line.a var b = line.b for (let i = 0; i < array.length; i++) { if (array[i] == a * i + b) { line.points.push({ x: i, y: array[i] }) } } line.length = line.points.length } console.log(JSON.stringify(slopes, null, 2)) } main()