如何使用python对markdown文档图片地址批量处理？-灵析社区

import re def process_markdown_content(content): img_pattern = re.compile(r'!\[([^\]]*)\]\((\./[^)]+)\)') # 对每个链接进行处理 def replacer(match): description = match.group(1) old_path = match.group(2) # 改图片链接为新的文件夹 new_path = old_path.replace('./', './new_folder/') return f'' # 替换原链接为新链接 new_content = img_pattern.sub(replacer, content) return new_content # 示例 markdown_content = ''' Here is some markdown content.   ''' new_content = process_markdown_content(markdown_content) new_content